Answer:
Third table [tex]m = \frac{-3}{4}[/tex]
The slope of the line
[tex]m = \frac{-3}{4}[/tex]
The equation of the straight line
3 x + 4y = 0
Step-by-step explanation:
Explanation:-
Given that the points are ( - 4,3) and (0,0)
The slope of the straight line
[tex]m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]
[tex]m = \frac{0-3 }{0-(-4)} = \frac{-3}{4}[/tex]
The equation of the straight line
y - ( 3 ) = [tex]\frac{-3}{4}[/tex] ( x - (-4))
4( y-3) = -3( x +4)
4 y - 12 = - 3x -12
3 x + 4y = 0
