Given :
A gas with a volume of 2 L at 25°C is placed into a container that is 4 L.
To Find :
The new temperature of the gas.
Solution :
Since, their is no information regarding pressure. We will assume that pressure is constant.
Now, we know when at constant pressure, volume is directly proportional to volume.
[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\\dfrac{2}{4} = \dfrac{25 + 273 }{x}\\\\x = 2 \times ( 25 + 273 )\\\\x = 596\ K[/tex]
Therefore, the new temperature of the gas is 596 - 273 K = 323 K.
