Answer:
The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams
Explanation:
The question is with regards to density calculations
The density of the given sodium carbonate solution, ρ = 0.4 g/dm³
The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³
[tex]Density \ of \ an \ object, \rho = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }[/tex]
[tex]\rho = \dfrac{m}{V}[/tex]
Therefore, we have;
[tex]The \ Density \ of \ the \ sodium \ carbonate, \ \rho = 0.4 \ g/dm^3 = \dfrac{m }{ 0.01 \ dm^3 }[/tex]
The mass, "m", of the sodium carbonate in = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g
The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.
