Step-by-step explanation:
Given system of equations are :
-3y = x+5 ....(1)
y = 2x+2 ...(2)
We need to find the solution of the equations.
Multiply equation (2) by 2.
-6y = 2x+10 ...(3)
Subtract equation (2) and (3).
y-(-6y)= 2x+2-(2x+10)
7y=2x+2-2x-10
7y=-8
y = 8/7
Put the value of y in equation (2)
[tex]\dfrac{8}{7}=2x+2\\\\\dfrac{8}{7}-2=2x\\\\x=\dfrac{\dfrac{-6}{7}}{2}\\\\x=\dfrac{-3}{7}[/tex]
Hence, this is the required solution.