Answer:
0.79dm³
Explanation:
The reaction expression is given as:
2H₂S + 3O₂ → 2SO₂ + 2H₂O
Volume of hydrogen sulfide = 500cm³ = 0.5dm³
Unknown:
volume of oxygen that reacted = ?
Solution:
At rtp;
22.4dm³ of gas has a mole of 1
0.5dm³ will [tex]\frac{0.5}{22.4}[/tex] = 0.022mole of hydrogen sulfide;
2 mole of H₂S combines with 3 mole of O₂
0.022 mole of H₂S will combine with [tex]\frac{0.022 x 3}{2}[/tex] = 0.033mole of O₂
So;
Since;
1 mole of a gas occupied a volume of 22.4dm³ at rtp;
0.033mole of Oxygen gas will occupy 0.033 x 22.4 = 0.79dm³
