The function f(x)=x(200-x) models the area of a pasture, in square yards, as a function of its length. Which are possible lengths of the pasture? 125 yards 200 yards 170 yards 225 yards 210 yards

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Answer:

(a): x = 125 yards.

(c): x = 170 yards.

Step-by-step explanation:

Given

[tex]f(x) = x(200 - x)[/tex]

[tex]x = length\\\\[/tex]

[tex]f(x) = area[/tex]

Required

Determine the possible length

For a length to be possible or usable, the calculated area must be greater than 0.

(a): x = 125 yards.

[tex]f(x) = x(200 - x)[/tex]

Substitute 125 for x

[tex]f(125) = 125 * (200 - 125)[/tex]

[tex]f(125) = 125 * 75[/tex]

[tex]f(125) = 9375[/tex]

(b): x = 200 yards.

[tex]f(x) = x(200 - x)[/tex]

Substitute 200 for x

[tex]f(200) = 200 * (200 - 200)[/tex]

[tex]f(200) = 200 * 0[/tex]

[tex]f(200) = 0[/tex]

(c): x = 170 yards.

[tex]f(x) = x(200 - x)[/tex]

Substitute 170 for x

[tex]f(170) = 200 * (200 - 170)[/tex]

[tex]f(170) = 200 * 30[/tex]

[tex]f(170) = 6000[/tex]

(d): x = 225 yards.

[tex]f(x) = x(200 - x)[/tex]

Substitute 225 for x

[tex]f(225) = 200 * (200 - 225)[/tex]

[tex]f(225) = 200 * (- 25)[/tex]

[tex]f(225) = -5000[/tex]

(e): x = 210 yards.

[tex]f(x) = x(200 - x)[/tex]

Substitute 210 for x

[tex]f(220) = 200 * (200 - 210)[/tex]

[tex]f(220) = 200 * (- 10)[/tex]

[tex]f(220) = -2000[/tex]

From the above calculations, only values of x that are 125 and 170 makes the function true

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