Question

A man gave each of 2 sons 1/3 of his herd of cows and sold 1/5 of the herd. What part of the head is left

Answer 1

Answer: $\dfrac2{15}$

Step-by-step explanation:

Given: Part of herd each son got = $\dfrac13$

Part of son 2 sons got = $2\times\dfrac13=\dfrac13$

Part of herd sold = $\dfrac15$

Then, part of the herd is left = $1-\dfrac{2}{3}-\dfrac15$  [ Consider whole part as 1.]

$=\dfrac{15-10-3}{15}\\\\=\dfrac{2}{15}$

Hence,  part of the herd is left = $\dfrac2{15}$