Question

A vessel contains 18.06*10^23 molecules of Ammonia gas at 25oc. Calculate the number of atoms present

Answer 1

Answer:  $72.3\times 10^{23}$ atoms

Explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to the molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}$

$[tex]\text{Number of moles of ammonia}=\frac{18.06\times 10^{23}}{6.023\times 10^{23}}=3moles$

As 1 mole of $NH_3$ contains = $4\times 6.023\times 10^{23}$ atoms

3 moles of $NH_3$ contains = $\frac{4\times 6.023\times 10^{23}}{1}\times 3=72.3\times 10^{23}$ atoms

Thus $72.3\times 10^{23}$ atoms are present