Answer:
(21, 0), (16, 1), (11, 2), (6, 3), (1, 4) are solutions of [tex]x + 5\cdot y = 21[/tex]. Please see the image attached below to know the plot on the coordinate plane.
Step-by-step explanation:
Let [tex]x + 5\cdot y = 21[/tex], we can determine five distinct points by transforming this function into its explicit form. That is:
[tex]x = 21 - 5\cdot y[/tex]
Then, we evaluate the function at five distinct values of [tex]y[/tex]:
y = 0
[tex]x = 21-5\cdot (0)[/tex]
[tex]x = 21[/tex]
y = 1
[tex]x = 21-5\cdot (1)[/tex]
[tex]x = 16[/tex]
y = 2
[tex]x = 21 - 5\cdot (2)[/tex]
[tex]x = 11[/tex]
y = 3
[tex]x = 21-5\cdot (3)[/tex]
[tex]x = 6[/tex]
y = 4
[tex]x = 21-5\cdot (4)[/tex]
[tex]x = 1[/tex]
(21, 0), (16, 1), (11, 2), (6, 3), (1, 4) are solutions of [tex]x + 5\cdot y = 21[/tex].