Answer:
0.422 M
Explanation:
Equation of the reaction,
2HCl(aq) + Ba(OH)₂(aq) ⇒ BaCl₂(aq)+2H₂O(l)
From the recation above,
2 moles of HCl is needed to neutralize 1 mole of Ba(OH)₂.
Using,
C'V'/CV = a/b......................... Equation 1
Where C' = concentration of acid, C = concentration of base, V' = volume of acid, V = volume of base, a = number of moles of acid, b = number of moles of base.
make C' the subject of the equation.
C' = aCV/bV'................. Equation 2
a = 2 mole, b = 1 mole, C = 0.0154 M, V = 27.4 mL, V' = 20 mL
Substitute into equation 2
C' = (2×0.0154×27.4)/(1×20)
C' = 0.422 M.
Hence the concentration of acid is 0.422 M
