Answer:
The answer is below
Step-by-step explanation:
The equation of a straight line is given by:
y = mx + b
where m is the slope of the line and b is the y intercept (value of y when x = 0).
Given the equation of two lines as [tex]y=m_1x+b_1\ and\ y=m_2x+b_2[/tex], the two lines are parallel to each other if [tex]m_1=m_2[/tex]. Also the lines are perpendicular if
[tex]m_1m_2=-1[/tex]
Given line BC:
3x + 2y = 8
2y = -3x + 8
y = -3x/2 + 4
Hence the slope of the line BC = -3/2
For line AD:
-3x - 2y = 6
-2y =3x + 6
y = -3x/2 - 3
Hence the slope of line AD is -3/2
Since both line BC and AD have equal slope (-3/2), hence both lines are parallel to each other
