Anyone can help?? I need it done before 9am please!!
![Anyone can help I need it done before 9am please class=](https://us-static.z-dn.net/files/d89/7af8812724388911efbc58dd7ecb510e.png)
Answer:
The answer is below
Explanation:
The equation for a linear line graph is given by:
y = mx + b, where y and x are variables, m is the slope of the graph and b is the y intercept (that is value of y when x is zero).
The slope (m) of a line passing through two points [tex](x_1,y_1)\ and\ (x_2,y_2)[/tex] is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
A) The first line passes through the point (0, 0) and (10, 60). It is represented as (time, velocity). Hence the slope is:
[tex]m=\frac{60 -0}{10-0}=6\ m/min^2[/tex]
B) The second line passes through the point (10, 60) and (15, 60). Hence the slope is:
[tex]m=\frac{60 -60}{15-10}=0\ m/min^2[/tex]
C) The third line passes through the point (15, 60) and (40, -40). Hence the slope is:
[tex]m=\frac{-40 -60}{40-15}=-4\ m/min^2[/tex]
D) The third line passes through the point (40, -40) and (55, 0). Hence the slope is:
[tex]m=\frac{0 -(-40)}{55-40}=2.67\ m/min^2[/tex]