Answer:
4). m∠DAE = 23°
5). m(∠BAE) = 29.5°
Step-by-step explanation:
4). "Angle formed by the intersection of two tangents and secants outside the circle is half of the difference of intercepted arcs"
m∠DAE = [tex]\frac{1}{2}(62-16)[/tex]
= [tex]\frac{46}{2}[/tex]
= 23°
5). Following the same rule as in question 4,
m(∠BAE) = [tex]\frac{1}{2} [m(\text{arc BE})-m(\text{arc CD})][/tex]
= [tex]\frac{1}{2}(88-29)[/tex]
= [tex]\frac{59}{2}[/tex]
= 29.5°
