Answer:
2AlBr₃[tex]_{aq}[/tex] + 3Cl₂[tex]_{g}[/tex] → 2AlCl₃[tex]_{aq}[/tex] + 3Br₂[tex]_{g}[/tex]
Explanation:
The word equation is:
Aqueous aluminum bromide and chlorine gas react to form aqueous aluminum chloride and bromine gas
Reactants:
aluminum bromide = AlBr₃
chlorine gas = Cl₂
Products:
aluminum chloride = AlCl₃
bromine gas = Br₂
So;
2AlBr₃[tex]_{aq}[/tex] + 3Cl₂[tex]_{g}[/tex] → 2AlCl₃[tex]_{aq}[/tex] + 3Br₂[tex]_{g}[/tex]
