What is the specific heat of an unknown substance if a 14 g sample releases 60 calories as its temperature changes from 40°C to 10°C? SHOW YOUR WORK​

Respuesta :

Answer:

Cp = 0.142 [cal/g*°C].

Explanation:

In order to solve this problem, we must use the following equation of thermal energy.

[tex]Q=m*c_{p}*(T_{initial}-T_{final})[/tex]

where:

Q = heat energy = 60 [cal]

Cp = specific heat [cal/g*°C]

T_final = final temperature = 10[°C]

T_initial = initial temperature =40[°C]

m = mass of the substance = 14 [g]

Now replacing:

[tex]60=14*C_{p}*(40-10)\\C_{p}=0.142[\frac{cal}{g*C} ][/tex]

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