The area of the first figure is 629.86 sq. meters and for the second figure, the combined area would be 430.18 629.86 sq. meters.
What is the area of the rectangle?
The area of the rectangle is the product of the length and width of a given rectangle.
The area of the rectangle = length × Width
For the first figure, we need to find the area of the semicircles and the area of the rectangle, then we get the combined area that gives the area of the figure.
The length of the rectangle is 28m. we can see that the diameter of the semicircle is equal to half of the length of the rectangle.
So. D = 14m and radius = 7m
The area of the 2 semicircles = [tex]\pi r^2[/tex]
= π x 7 x 7
= 49π sq. meter
The breadth of the rectangle = 24 - r
= 24 - 7
= 17m
The area of the rectangle = length × Width
= 28 x 17
= 476 sq. meter
The combined area = 629.86 sq. meter
B. The area of the 2 semicircles = [tex]\pi R^2[/tex] + [tex]\pi r^2[/tex]
= π ( 11 x 11 + 4 x 4)
= 3.14 x (121 + 16)
= 430.18 sq. meter
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