Question

A 2.0 x 10^3 kilogram car collides with a tree and is brought to
rest in 0.50 seconds by an average force of 6.0 x 10^4 newtons.
What is the magnitude of the impulse on the car during this
0.50 second interval?

Answer 1

Answer:

P = 30000 [kg*m/s]

Explanation:

Momentum in physics is defined as the product of force in the given time interval. In this way, it can be expressed by means of the following equation.

$P=F*t$

where:

P = momentum [kg*m/s]

F = force = 6*10⁴ [N]

t = 0.5 [s]

Now replacing:

$P=6*10^{4}*0.5\\P=30000[kg*m/s]$