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NASA launches a rocket at t=0 seconds. It’s height, in meters above sea-level, as a function of time is given by h=-4.9t^2+313t+325

(a) assuming that the rocket will splash down into the ocean, at what time does splashdown occur? (Round answer to 2 decimal places)

The rocket splashes down after .... seconds

(b) how high above sea-level after seconds

The rocket peaks at .. meters above sea-level

Respuesta :

Answer:

-4.9t^2 + 160t + 290 = 0

t = [-160 +- sqrt(160^2 - 4*-4.9*290)]/(2*-4.9)

Positive Solution::

t = 34.37 seconds

Step-by-step explanation:

Answer:

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Step-by-step explanation:hhgdfhhjjhg

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