Question

how to solve (x+y)^2 + (x^2 -2xy+y^2)

Answer 1

Answer:

2$x^{2}$+2$y^{2}$

Step-by-step explanation:

$(x+y)^{2}$ + ($x^{2}$ -2xy+$y^{2}$)

(x+y)(x+y)+($x^{2}$ -2xy+$y^{2}$)

$x^{2}$+ xy + xy+$y^{2}$+$x^{2}$-2xy+$y^{2}$

$x^{2}$+2xy+$y^{2}$+$x^{2}$-2xy+$y^{2}$ (cancel 2xy)

The answer is  -      2$x^{2}$+2$y^{2}$