Question

A rifle is aimed horizontally at the center of a large target 60 m away. The initial speed of the bullet is 240 m/s. What is the distance from the center of the target to the point where the bullet strikes the target

Answer 1

Answer:

The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

Explanation:

Given;

the position of center of the target, x₀ = 60 m

initial velocity of the bullet, u = 240 m/s

The time the bullet strikes the center of the large target is calculated as;

$t = \frac{x_o}{u} =\frac{60}{240} = 0.25 \ s$

The distance from the center of the target to the point where the bullet strikes the target is calculated as;

x = vt + ¹/₂gt²

where;

v is the final velocity of the bullet when it strikes the target = 0

x = 0 + ¹/₂(9.8)(0.25²)

x = 0.31 m

Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.