Answer: 2.58 days
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant = ?
t = age of sample = 6 days
a = initial amount of the reactant = 1 g
a - x = amount left after decay process = 0.2 g
a) to find the rate constant
[tex]6=\frac{2.303}{k}\log\frac{1.0}{0.2}[/tex]
[tex]k=\frac{2.303}{6}\log\frac{1.0}{0.2}[/tex]
[tex]k=0.268days^{-1}[/tex]
b) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days[/tex]
The half life is 2.58 days