picture is shown above
suppose that y varies directly with x, and y=12 when x=15

Step-by-step explanation:
Since y is directly proportional to x,
we have y = kx, where k is a real constant.
When x = 15, y = 12.
=> (12) = k(15), k = 0.8.
Therefore we have y = 0.8x.
When x = 2, y = 0.8(2) = 1.6.
The answer is y = 1.6 when x = 2.
Answer:
y is directly proportional to x
y=kx, where k is a constant
Now, y=12 when x=15
[tex]12 = k \times 15 \\ k = \frac{12}{15} \\ \boxed{k = 0.8}[/tex]
When x=2,
[tex]y = 0.8 \times 2 \\ \boxed{y = 1.6}[/tex]