Question

Based on a study by Dr. P. Sorita Soni at Indiana University, assume that eye colors in the United States are distributed as follows: 40% brown, 35% blue, 12% green, 7% gray, 6% hazel. If three people are randomly selected, what is the probability that one will have brown eyes, one will have gray eyes, and one will have green eyes (with replacement)

Answer 1

Answer

0.00336

Step-by-step explanation:

Given :

P(Brown), P(Br) = 0.4

P(Blue) = P(b= 0.35

P(green,) = P(g) = 0.12

P(gray), P(Gr) = 0.07

If 3 individuals are selected, the probability that one has brown eye, 1 has Grey and one has green.

Since the probabilities are independent :

P(Br) * P(Gr) * P( g)

0.3 * 0.07 * 0.12

= 0.00336