Jamie is an analyst at an education technology company. She gathered data on the results of a certain type of question. Of the 2,000 responses she looked at, 1,092 responded correctly. What equation could Jamie use to calculate the margin of error at a 90% confidence interval?

Jamie is an analyst at an education technology company She gathered data on the results of a certain type of question Of the 2000 responses she looked at 1092 r class=

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Answer:

1st Square - 1.65

2nd Square - 0.546

3rd Square - 0.546

4th Square - 2000

(got it right on edmentum)

for better understanding of what I mean please take your time to look at the picture below↓

Step-by-step explanation:

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The margin of error for the 90% confidence interval with a probability of success of 0.546 is 0.0183.

What is the margin of error?

The probability or the chances of error while choosing or calculating a sample in a survey is called the margin of error.

Jamie is an analyst at an education technology company. She gathered data on the results of a certain type of question. Of the 2,000 responses she looked at, 1,092 responded correctly.

Then the value of p will be

[tex]\rm p = \dfrac{1092}{2000}\\\\p = 0.546[/tex]

And the z-value for the 90% confidence interval will be

[tex]\rm z = 1.645[/tex]

And N = 2000

Then the margin of error (ME) will be

[tex]ME = z \times \sqrt{\dfrac{p(1-p)}{N}}\\\\ME = 1.645\times \sqrt{\dfrac{0.546(1-0.546)}{2000}}\\\\ME = 0.0183[/tex]

More about the margin of error link is given below.

https://brainly.com/question/6979326

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