Respuesta :
We have that for the Question it can be said that the volume of water must be added to 250 mL of a 25% w/v stock solution of sodium chloride to prepare a 0.9% w/v sodium chloride solution is
x=444ml
From the question we are told
. H ow many milliliters of water must be added to 250 mL of a 25% w/v stock solution of sodium chloride to prepare a 0.9% w/v sodium chloride solution
Generally the equation for the volume of NaCl is mathematically given as
[tex]V=\frac{25}{100}*250\\\\V=62.5ml[/tex]
Therefore
[tex]\frac{62.5}{250+x}*100=0.9\\\\x=6250-2250\\\\x=4000ml\\\\x=444ml[/tex]
Therefore
the volume of water must be added to 250 mL of a 25% w/v stock solu- tion of sodium chloride to prepare a 0.9% w/v sodium chloride solution is
x=444ml
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