Answer:
The molecular formula of the compound is C₂H₄F₂ or CH₃CHF₂
Explanation:
From the question given above, the following data were obtained:
Empirical formula of the compound = CH₂F
Fórmula mass of compound = 66 g/mol
Molecular formula of the compound =?
The molecular formula of the compound can be obtained as follow:
Molecular formula = [Empirical formula]ₙ
Molecular formula = [CH₂F]ₙ
[CH₂F]ₙ = 66
[12 + (2×1) + 19] n = 66
[12 + 2+ 19]n = 66
33n = 66
Divide both side by 33
n = 66/33
n = 2
Molecular formula = [CH₂F]ₙ
Molecular formula = [CH₂F]₂
Molecular formula = C₂H₄F₂
Thus, the molecular formula of the compound is C₂H₄F₂ or CH₃CHF₂
