Answer:
ΔH 263 < ΔH 273
Explanation:
From the given information
According to Kirchoff law:
[tex]\Delta H_2 = \Delta \ H_1 + \Delta \ (c_p) ( \Delta T)[/tex]
[tex]\Delta H_2 = \Delta \ H_1 + (76-37) \times ( 273 - 263)[/tex]
[tex]\Delta H_2 = \Delta \ H_1 + (39) \times (10)[/tex]
[tex]\Delta H_2 = \Delta \ H_1 + 390[/tex]
Thus, [tex]\Delta H_2[/tex] at 273 is greater than [tex]\Delta \ H_1[/tex] at 263
∴
ΔH 263 < ΔH 273