Question

Consider Argon at 500 K and 500 kPa inside a rigid tank. The surrounding pressure is 100 kPa. Determine the specific volume. Report you answer based on units of m^3 /kg. Report your answer to three significant digits. However, do not include units in your answer.

Answer 1

Answer:

0.208 m³/kg

Explanation:

We have these information to answer this question

Temperature T = 500K

Pressure p = 500Kpa

R = 0.2801kj/kgK

We know that

Pv = mRT

Such that,

v/m = RT/P

Then

When we put these values into the above formula, we have

Vs = 0.2081 x 500/500

= 0.2081 x 1

= 0.208 m³/ kg to 3 significant figures

This is therefore the specific volume.

Thank you!