Answer:
ΔQ = 5054 KJ/kg.K
Explanation:
First of all, we will find the value of the specific heat of hydrogen. Since it is mentioned that the value of specific heat is constant between 300 K and 650 K. Therefore, we can take it to be the average of values at these two temperatures.
[tex]Constant\ Specific\ Heat\ of\ Hydrogen = C = \frac{Specific\ Heat\ at\ 300\ K + Specific\ Heat\ at\ 650\ K}{2} \\C = \frac{(14.31 + 14.57)KJ/ kg.K}{2}[/tex]C = 14.44 KJ/ kg.K
Now, the heat absorbed is given by the following formula:
[tex]\Delta Q = C(T_{f} - T{i})[/tex]
where,
T_f = Final Temperature = 650 K
T_i = Initial Temperature = 300 K
[tex]\Delta Q = (14.44\ KJ/kg.K)(650\ K - 300\ K)\\[/tex]
ΔQ = 5054 KJ/ kg.K