Answer: 0.03532
Step-by-step explanation:
Given : p = 0.07 , n= 550
Binomial probability distribution: [tex]P(X=x)=\ ^nC_xp^x(1-p)^{n-x}[/tex]
The probability that exactly 45 of the accounts will be delinquent will be :
[tex]P(X=45) = \ ^{550}C_{45}(0.07)^{45}(1-0.07)^{550-45}\\\\= \dfrac{550!}{45!505!}(0.07)^{45}(1-0.07)^{505}\\\\\approx0.03532[/tex]
Hence, the required probability = 0.03532