Answer:
t = 11.9 h = 0.49 day
Explanation:
First of all, we will find the area covered by the mower per unit time:
[tex]Rate\ of\ Area\ Covered\ by\ Mower = vw[/tex]
where,
v = speed of mower = 1 km/h = 1000 m/h
w = width of mower = 0.6 m
Therefore,
[tex]Rate\ of\ Area\ Covered\ by\ Mower = (1000\ m/h)(0.6\ m)\\Rate\ of\ Area\ Covered\ by\ Mower = 600\ m^{2}/h[/tex]
Now, the standard football ground has an area of:
A = 105 m x 68 m = 7140 m²
Therefore, The time required to mow the lawn will be:
[tex]Time\ to\ Mow\ the\ Lawn = t = \frac{A}{Rate\ of\ Area\ Covered\ by\ Mower}\\t = \frac{7140\ m^{2}}{600\ m^{2}/h}[/tex]
t = 11.9 h = 0.49 day