Question

g We have 5 red and 10 blue devices. The probability of the failure for the red devices is 1/2 while the probability of the failure for the blue devices is 1/4. If we randomly pick a device, what is the probability of its failure

Answer 1

Answer:

5 / 8

Step-by-step explanation:

Given :

Red devices = 5

Blue devices = 10

P(red failure) = 1/2

P(blue failure) = 1/4

Probability of failure if we pick a device equals ; P(red failure) or P(bue failure) =P(RuB)

P(RuB) = P(red failure) + P(Blue failure) - P(RnB)

P(RnB)

P(P(red failure) * P(Blue failure)

1 / 2 * 1/ 4

= 1/ 8

P(RuB) = P(red failure) + P(Blue failure) - P(RnB)

P(RuB) = 1/2 + 1/4 - 1/8

P(RuB) = 3/4 - 1/8 = (6 - 1) / 8 = 5/8

Hence, probability of failure is 5/8

Answer 2

The probability of its failure will be 5/8

Probability

Probability is the likelihood or chance that an event will occur.

Given the following information

• Red devices = 5  
• Blue devices = 10
• P(red failure) = 1/2  

• P(blue failure) = 1/4

Probability of failure if we pick a device equals ;

• P(red failure) or P(blue failure) =P(RuB)

P(RuB) = P(red failure) + P(Blue failure) - P(RnB)  

P(RnB)   = P(P(red failure) * P(Blue failure)  = 1 / 2 * 1/ 4  = 1/ 8

Similarly;

P(RuB) = P(red failure) + P(Blue failure) - P(RnB)  

P(RuB) = 1/2 + 1/4 - 1/8

P(RuB)  = 5/8  

Hence, the probability of its failure will be 5/8

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