Answer: Margin of Error for the given CI is 0.08
Step-by-step explanation:
Given the data in the question;
it is a symmetric class interval hence, sample proportion p = (0.50 + 0.66) / 2
p = 1.16 / 2
sample proportion p = 0.58
Margin of Error E will be;
E = 1/2 × length of Confidence interval
Margin of Error E = 1/2 × ( 0.66 - 0.5)
Margin of Error E = 1/2 × 0.16
Margin of Error E = 0.08
Therefore; Margin of Error for the given CI is 0.08
