Question

Suppose that a recent poll of American households about pet ownership found that for households with pets, 45% owned a dog, 34% owned a cat, and 10% owned a bird. Suppose that three households are selected randomly and with replacement and the ownership is mutually exclusive. What is the probability that all three randomly selected households own a dog

Answer 1

Answer: 0.091125

Step-by-step explanation:

Given : P(dog) = 0.45

If 3 households are selected randomly and with replacement and the ownership is mutually exclusive.

Then , probability that all three randomly selected households own a dog = $(0.45)^3=0.091125$

Hence, required probability = 0.091125

Answer 2

The probability that all three randomly selected households own a dog  is

0.091125.

Given that,

• Suppose that a recent poll of American households about pet ownership found that for households with pets, 45% owned a dog, 34% owned a cat, and 10% owned a bird.
• Three households are selected randomly and with replacement and the ownership is mutually exclusive.

Based on the above information, the calculation is as follows:

$= 0.45^3$

= 0.091125

Learn more: brainly.com/question/17429689