Question

A delivery truck hits a parked car from behind. The mass of the car is 2550 kg. What force is exerted on the car if (a) the car is rigid and accelerates to 4.5 m/s in 0.20 s? (b) the car has crumple zones and accelerates to 4.5 m/s in 0.30 s?
Helpp meee........TT​

Answer 1

Explanation:

Given parameters:

Mass of the car  = 2550kg

Initial velocity  = 0m/s

Solution:

First problem is to find the force exerted on the car;

  Velocity  = 4.5m/s

   Time  = 0.2s

Acceleration  = $\frac{final velocity - initial velocity }{time}$   = $\frac{4.5 - 0}{0.2}$  = 22.5m/s²  

Force  = mass x acceleration  = 2550 x 22.5  = 57375N

B. Force on the car with crumple zones

Acceleration  = $\frac{final velocity - initial velocity }{time}$    = $\frac{4.5 - 0}{0.3}$   = 15m/s²

 Force  = 2550 x 15  = 38250N

Answer 2

a. The force when the car is rigid and accelerated is 57375N.

b. The force where the car should have  crumple zones should be 38250N

Calculation of the force:

Since Mass of the car  = 2550kg

Initial velocity  = 0m/s

Here,

Velocity  = 4.5m/s

Time  = 0.2s

a.

Here force = mass * acceleration

= 2550 * (4.5 - 0/0.2)

= 2550 * 22.5

= 57375 N

b.

Here force is

= mass * acceleration

= 2550 * (4.5 - 0/0.3)

= 2550 * 15

= 38250 N

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