Question

A sports car accelerates from rest to 42 m/s in 6.2 s, what is its acceleration? (6.8 m/s) with proof please

Answer 1

Answer:

Explanation:

As the car Started from rest means that Initial Velocity "Vi = 0 m/s" and final Velocity is given "Vf = 42m/s". Time is given "t = 6.2s"

Acceleration is required a =?

Use Formula;;    a = $\frac{Vf-Vi}{t}$

a = $\frac{42-0}{6.2}$

a = 6.7741 m/s² ≈ 6.8 m/s²

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