Answer:
13.3 mol
Explanation:
Given data:
Number f moles of O₂= 10 mol
Moles of AlBr₃ react = ?
Solution:
Chemical equation:
3O₂ + 4AlBr₃ → 2Al₂O₃ + 12Br
Now we will compare the moles of oxygen and AlBr₃
O₂ : AlBr₃
3 : 4
10 : 4/3×10 = 13.3 mol
Thus, to react with 10 moles of oxygen 13.3 moles of AlBr₃ are required.