Answer:
The extension of the spring is 7.35 cm
Explanation:
Spring Force
When a spring is compressed or extended by a distance x, it exerts a force given by the Hooke's Law:
F=k.x
Where k is the constant of the spring.
A mass of m=75 gr is hung to the spring of constant k=10 N/m. The force applied to the spring is the weight of the mass:
W = mg
The mass must be converted to kg:
m = 75/1000 = 0.075 kg
W=0.075*9.8
W = 0.735 N
The extension of the spring can be computed by solving for x:
[tex]\displaystyle x=\frac{0.735}{10}[/tex]
x=0.0735 m
x = 7.35 cm
The extension of the spring is 7.35 cm
