Question

given AC with A(3,4) and C(-9,-2) if B partitions AC such that the ratio of AB to BC is 1:5 find the coordinates of B. ​

Answer 1

Answer:

The co-ordinates of B (1,3 )

Step-by-step explanation:

Step(i):-

Given A( 3,4) and C( -9, -2)

Given  'B' partition AC such that

B divides AC in the ratio is 1:5 internally

Section formula

       $(\frac{mx_{2}+nx_{1} }{m+n} ,\frac{my_{2}_+ny_{1} }{m+n} )$

Step(ii):-

Given points are

     A( 3,4) and C( -9, -2) and ratio 1 : 5

(x₁ , y₁) = ( 3,4)     and (x₂, y₂) = (-9,-2)

m:n = 1 : 5

The co-ordinates of B

           = $(\frac{1(-9)+5(3) }{1+5} ,\frac{1(-2)+5(4) }{1+5} )$

         =  $(\frac{6}{6} , \frac{18}{6} )$

       = (1 , 3)

Final answer:-

The co-ordinates of B (1,3 )