Question

PLEASE HELP ME!!!! WILL GIVE BRAINLIEST!!!!

1. What is the molality of a solution made up of 43.6 mol of CaCl2 dissolved by 13.5 kg of water?

2. How many moles of Na2CO3 are required to create 9.54 liters of a 3.4 M solution?

3. Which of these actions can result in decreasing the molarity of a solution?

Select all that apply.

A

adding solute

B

adding solvent

C

removing solute

D

removing solvent

Thanks Y'all:)

Answer 1

Answer: 1. 3.23 m

2. 32.4

3. B  adding solvent  and C  removing solute

Explanation:

1. Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent

$Molality=\frac{n}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent

Now put all the given values in the formula of molality, we get

$Molality=\frac{43.6mol}{13.5kg}=3.23mol/kg$

2. Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

$3.4=\frac{n}{9.54}$

$n=32.4$

Therefore, the moles of $Na_2CO_3$ is 32.4

3. Molarity can be decreased by decreasing the moles of solute and by increasing the volume of solution.

Thus adding solvent  and removing solute will decrease the molarity.