Question

Find the equation of the line that passes through (-1,2) and is perpendicular to 2y = 2x – 1.
Leave your answer in the form y = mx + c

Answer 1

Step-by-step explanation:

question is solved above in the picture

Answer 2

The equation of line that passes through point (-1,2) and which is perpendicular to 2y = 2x – 1 will be y = -x + 1.

Equation of line

The General equation of a line is ax + by + c = 0

How to solve this problem?

• Since the line is perpendicular to 2y=2x-1, this means that its slope with be the opposite reciprocal of the line 2y=2x-1 ‘s slope.
• First, we should find the slope of the line 2y=2x-1:

2y=2x-1

y=x-1/2

• Therefore, the slope of 2y=2x-1 is 1 and the opposite reciprocal of 1 is -1

• So far, we have this: y=-x+b

• To find b (the y-intercept) we can plug the point (-1,2) into the equation we have so far and solve for b.

y=-x+b

2=-(-1)+b

2=1+b

b=1

So, the equation of the line that passes through (-1,2) and which is perpendicular to 2y=2x-1 is y=-x+b

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