Question

The drawing shows Robin Hood (mass = 83.4 kg) about to escape from a dangerous situation. With one hand, he is gripping the rope that holds up a chandelier (mass = 243.0 kg). When he cuts the rope where it is tied to the floor, the chandelier will fall, and he will be pulled up toward a balcony above. Ignore the friction between the rope and the beams over which it slides, and find:

a. the acceleration with which Robin is pulled upward.
b. the tension in the rope while Robin escapes.

Answer 1

Answer:

$a=4.797791411m/s^2\\a\approx4.8m/s^2$

$T=1217.64N$

Explanation:

From the question we are told that

Mass of Robin $M_R=83.4kg$

Mass of chandelier $M_c= 243.0 kg$

a)Generally the equation for acceleration in system is mathematically given by

$a=\frac{m_2-m_1}{m_1+m_2} g$

$a=\frac{243.0-83.4}{243.0+83.4} *9.8$

$a=\frac{159.6}{326} *9.8$

$a=\frac{1564.08}{326}$

$a=4.797791411m/s^2\\a\approx4.8m/s^2$

b)Generally the equation for Tension is given mathematically as

$T=m_1a+m_1g$

$T=83.4(4.8+9.8)$

$T=1217.64N$