A sample of carbon monoxide gas occupies 3.20 L at
125 °C. At what temperature will the gas occupy a
volume of 1.54 L if the pressure remains constant?​

Respuesta :

The final temperature : 191.54 K = -81.46 °C

Further explanation

Given

V₁=3.2 L

T₁ = 125 +273 = 398 K

V₂=1.54 L

Required

The final temperature(T₂)

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

T₂=(V₂T₁)/V₁

T₂=(1.54 x 398)/3.2

T₂=191.54 K = -81.46 °C

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