Answer:
Explanation:
gauge pressure due to a liquid column of density d and height h is given by the following expression .
P = hdg
The pressure depends upon height of liquid column and not on the cross sectional area .
In first cylinder .
gauge pressure = .40 atm
hdg = .40 atm
cross sectional area of cylinder = π r²
The radius of second cylinder is twice of the first , cross sectional area will be 4 times .
The volume remains the same when the liquid is poured into second cylinder
volume = cross sectional area x height .
As cross sectional area of second cylinder is 4 times , height of liquid column in second cylinder = h / 4 .
gauge pressure in second cylinder = h / 4 x d x g = hdg / 4
.40 / 4 = .10 atm
gauge pressure in second cylinder = .10 atm.
