Question

Cream of tartar, a common ingredient in cooking, is the common name for potassium bitartrate (abbreviated KBT, molar mass 188.2 g/mol). Historically, KBT was a crystalline solid that formed on the casks of wine barrels during the fermentation process. Calculate the maximum mass of KBT that can dissolve in 280. mL of solution to make a saturated solution. KBT dissolves to form the potassium ion (K+) and the bitartrate ion (abbreviated as BT-).
KBT(s) → K+(aq) + BT-(aq) Ksp = 3.8×10-4

Answer 1

Answer:

0.288g KBT can be dissolved

Explanation:

The dissolution of KBT produce the dissociation in K⁺ and BT⁻ ions as follows:

KBT(s) → K+(aq) + BT-(aq) Ksp = 3.8×10-4

Where Ksp is defined as:

Ksp = 3.8x10⁻⁴ = [K⁺][BT⁻]

Thus, we need to find the concentration of KBT that can be dissolved = [K⁺] = [BT⁻]:

3.8x10⁻⁴ = [K⁺][BT⁻]

3.8x10⁻⁴ = [KBT][KBT]

3.8x10⁻⁴ = [KBT]²

0.01949M = [KBT]

In 280mL = 0.280L, the moles of KBT that can be dissolved are:

0.01949mol / L * 0.280L =

5.458x10⁻³ moles of KBT. In grams (Using molar mass):

5.458x10⁻³ moles of KBT * (188.2g/mol) =

0.288g KBT can be dissolved