guys please help this is a math question
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Answer:
81.5
Step-by-step explanation:
<G and <H are congruent
<F and <I are congruent
so the last two angles in both triangles must also be congruent
this means that <K and <J are congruent
so we can create this equation: <K = <J
substitute the angles with what we know: 4[tex]y^{2}[/tex] = 6[tex]y^{2}[/tex] - 40
add 40 to both sides and subtract 4[tex]y^{2}[/tex] from both sides: 40 = 2[tex]y^{2}[/tex]
you get: 20 = [tex]y^{2}[/tex]
root square on both sides: [tex]\sqrt{20}[/tex] = [tex]\sqrt{y^{2} }[/tex]
you get: y ≈ 4.5
substitute this into one of the equations for a missing variable:
6[tex]y^{2}[/tex] -----> 6 (4.5 x 4.5) - 40
6 ( 20.25) - 40
121.5 - 40
81.5