The increase in thermal energy of the gas sample is +14 J, and the temperature is increased.
Given information:
The heat removed from the gas sample is [tex]Q=-14\rm\;J[/tex]. The negative sign represents the heat removal.
The work done on the gas sample is [tex]W=28\rm\; J[/tex].
Work is done on the gas. So, it will be taken as positive.
According to the first law of thermodynamics, the change in thermal energy of the gas or system will be calculated as,
[tex]\Delta E=Q+W\\\Delta E=-14+28\\\Delta E=14\rm\;J[/tex]
The change in thermal energy of the system will be 14 J. It is positive. So, the thermal energy is increased. It implies the temperature of the system or gas is also increased.
Therefore, the increase in thermal energy of the gas sample is +14 J, and the temperature is increased.
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