A hemispherical tank is filled with water and has a diameter of 14 feet. If water
weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank,
to the nearest pound?

Respuesta :

Answer:

[tex]44,826.72\ \text{pounds}[/tex]

Step-by-step explanation:

Given that,

The diameter of a hemispherical tank= 14 feet

Radius, r = 7 feet

water

Water weighs 62.4 pounds per cubic foot.

We need to find the total weight of the water in a full tank to the nearest pound.

The volume of the hemisphere is given by :

[tex]V=\dfrac{2}{3}\pi r^3\\\\V=\dfrac{2}{3}\pi \times (7)^3\\\\V=718.377\ \text{feet}^3[/tex]

If water weighs 62.4 pounds per cubic foot, it means

[tex]V=718.377\times 62.4\\\\V=44,826.72\ \text{pounds}[/tex]

So, the total weight of the water is [tex]44,826.72\ \text{pounds}[/tex].

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