Question

Which shows the following expression after the negative exponents have been eliminated?
A^3 b^-2/ab^-4
A=/0, b=/0

Answer 1

Answer:

$\frac{a^3b^{-2}}{ab^{-4}} = a^{2}b^{2}$

Step-by-step explanation:

Given

$\frac{a^3b^{-2}}{ab^{-4}}$

$a\ne 0; b \ne 0$

Required

Evaluate

$\frac{a^3b^{-2}}{ab^{-4}}$

Apply the following law of indices:

$\frac{x^m}{x^n} = x^{m-n}$

So, the expression becomes:

$\frac{a^3b^{-2}}{ab^{-4}} = a^{3-1}b^{-2-(-4)}$

Remove brackets

$\frac{a^3b^{-2}}{ab^{-4}} = a^{3-1}b^{-2+4}$

$\frac{a^3b^{-2}}{ab^{-4}} = a^{2}b^{2}$

Answer 2

Answer:

D. a^3 b^4 / ab^2

Step-by-step explanation: