if tan theta= -0.87, find cot
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Answer:
Step-by-step explanation:
[tex]cot(\frac{\pi }{2} -\theta)=tan \theta=-0.87[/tex]
or second method
[tex]\cot(\frac{\pi }{2} -\theta)=\frac{1}{\tan(\frac{\pi }{2} -\theta)} =\frac{1}{\frac{\tan\frac{\pi }{2} -\tan \theta}{1+\tan \frac{\pi }{2 } \tan \theta} } =\frac{1+\tan\frac{\pi }{2} \tan \theta}{\tan\frac{\pi }{2} -\tan \theta} \\(divide~the~numerator~and~denominator~by~\tan\frac{\pi }{2} )[/tex]
[tex]=\frac{\cot\frac{\pi }{2} +\tan\theta}{1-\cot\frac{\pi }{2} \tan\theta} \\=\frac{0+\tan \theta }{1-0*\tan\theta} \\=\tan \theta\\=-0.87[/tex]